អូឌីយ៉ូ​ដែល​បាន​ចែករំលែក

Continuing with our Second Iteration, let's finish distributing the trips for Zone 1. First, T {1 2} remains zero. Even though we are in a second iteration, the base attraction for Zone 2 is still zero, so no trips will be distributed there. Now, let's look at T {1 3}, the trips from Zone 1 to Zone 3. To find this, we first establish our new system denominator. Using our adjusted attractions of 1,121 for Zone 1 and 7,282 for Zone 3, we calculate a total accessibility factor of 444.9. When we plu